Question

A uniform rod of length and mass M is suspended on two vertical inextensible strings as shown in the figure. Calculate tension T in left string at the instant, when right string snaps.

• A. $\frac { m g } { 2 }$
• B. mg
• C. $\frac { m g } { 4 }$
• D.

Answer 1

Answer: (C)

$\frac { m g } { 4 }$

Answer 2

Let the tension in the rope be T and the acceleration of the centre of mass of the rod downwards be a.

Then mg − T = ma . . . (1)

Again, $\frac { \mathrm { mg } \ell } { 2 }$ = Iα =

⇒ a = . . . (2)

∴ T = , Hence,