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Question: A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface by a constant horizon...

A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface by a constant horizontal force F. The area of cross-section of the plank is A. the compressive strain on the plank in the direction of the force is

A

FAY\frac{F}{AY}

B

2FAY\frac{2F}{AY}

C

12(FAY)\frac{1}{2}\left( \frac{F}{AY} \right)

D

3FAY\frac{3F}{AY}

Answer

FAY\frac{F}{AY}

Explanation

Solution

Compressive strain =StressYoung’s modulus= \frac{\text{Stress}}{\text{Young's modulus}} =F/AY=FAY= \frac{F/A}{Y} = \frac{F}{AY}