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Question

Physics Question on Newtons Laws of Motion

A uniform metal chain of mass m and length ‘LL’ passes over a massless and frictionless pully. It is released from rest with a part of its length ‘ll’ is hanging on one side and rest of its length 'LlL – l' is hanging on the other side of the pully. At a certain point of time, when l=L/xl = L/x, the acceleration of the chain is g/2g/2. The value of xx is ______.

Uniform metal chain of mass m and length ‘L’ passes over a massless and frictionless pully

A

6

B

2

C

1.5

D

4

Answer

4

Explanation

Solution

a=(m2m1)(m2+m1)ga = \frac{(m_2 - m_1)}{(m_2 + m_1)}gg2\frac{g}{2} = (λ(Ll)λl)gλL\frac{(λ(L - l) - λl)g}{λL}

L=L4=LxL = \frac{L}{4} = \frac{L}{x}

x=4x = 4