Question

A uniform magnetic field $\overrightarrow{B}=B_0\hat{z}$, where $B_0\gt0$ exists as shown in the figure. A charged particle of mass m and charge $q(q\gt0)$ is released at the origin, in the yz-plane, with a velocity $\overrightarrow v$ directed at an angle $\theta$= 45° with respect to the positive z-axis. Ignoring gravity, which one of the following is TRUE.

• A. The initial acceleration $\overrightarrow a=\frac{qvB_0}{\sqrt 2m}\hat x$
• B. The initial acceleration $\overrightarrow a=\frac{qvB_0}{\sqrt 2m}\hat y$
• C. The particle moves in a circular path
• D. The particle continues in a straight line with constant speed

Answer 1

Answer: (A)

The initial acceleration $\overrightarrow a=\frac{qvB_0}{\sqrt 2m}\hat x$

Answer 2

The correct answer is (A) : The initial acceleration $\overrightarrow a=\frac{qvB_0}{\sqrt 2m}\hat x$