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Question

Physics Question on Electromagnetic induction

A uniform magnetic field is restricted within a region of radius rr. The magnetic field changes with time at a rate dBdt\frac{d \vec{B}}{dt}. Loop 11 of radius R>rR > r enclosed the region rr and loop 22 of radius RR is outside the region of magnetic field as shown in the figure below. Then the e.m.f. generated is

A

Zero in loop 11 and zero in loop 22

B

dBdtπr2- \frac{d \vec{B}}{dt} \pi r^2 in loop 11 and dBdtπr2- \frac{d \vec{B}}{dt} \pi r^2 in loop 22

C

dBdtπR2- \frac{d \vec{B}}{dt} \pi R^2 in loop 11 and zero in loop 22

D

dBdtπr2- \frac{d \vec{B}}{dt} \pi r^2 in loop 11 and zero in loop 22

Answer

dBdtπr2- \frac{d \vec{B}}{dt} \pi r^2 in loop 11 and zero in loop 22

Explanation

Solution

Induced e.m.f. in loop (1)
e=dϕdt=AdBdte = - \frac{d\phi}{dt} =- \frac{AdB}{dt}
=πr2dBdt= - \pi r^{2} \frac{dB}{dt}
Induced e.m.f. in loop (2)
Loop (2) is not in magnetic field so no field change so induced e.m.f. = 0