Question

A uniform electric field vector $\vec{E}$ exists along horizontal direction as shown. The electric potential at A is VA . A small point charge q is slowly taken from A to B along the curved path as shown. The potential energy of the charge when it is at point B is

• A. q[VA + Ex]
• B. q[Ex - VA]
• C. qEx
• D. q[VA - Ex]

Answer 1

Answer: (D)

q[VA - Ex]

Answer 2

The correct answer is (D) : q[VA - Ex].