Question

A uniform electric field having a magnitude E₀ and direction along the positive x-axis exists. If the potential V is zero at X = 0, then its value at X = +x will be-

• A. V(x) = +XE₀
• B. V(x) = –XE₀
• C. V(x) = X²E₀
• D. V(x) = – X²E₀

Answer 1

Answer: (B)

V(x) = –XE₀

Answer 2

= E₀ , V(1) – V(0) = –

=$\frac { - \mathrm { dv } } { \mathrm { dr } }$ V(x) – V(0) = – E₀.x

V(x) – V(0) = –E₀x

Q V(0) = 0;\ V(x) = –E₀x