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Question: A uniform electric field \(E = 2 \times 10^{3}NC^{- 1}\) is acting along the positive x – axis. The ...

A uniform electric field E=2×103NC1E = 2 \times 10^{3}NC^{- 1} is acting along the positive x – axis. The flux through the same square if the line normal to its plane makes a 60o60^{o}angle with the x – axis is.

A

30 N C1m2C^{- 1}m^{2}

B

10 N C1m2C^{- 1}m^{2}

C

20 N C1m2C^{- 1}m^{2}

D

25 N C1m2C^{- 1}m^{2}

Answer

10 N C1m2C^{- 1}m^{2}

Explanation

Solution

: When normal to the plane makes an angle of 60o60^{o}with x –axis, then θ=60o\theta = 60^{o}

φ=EScosθ=2×103×102cos60o\varphi = ES\cos\theta = 2 \times 10^{3} \times 10^{- 2}\cos 60^{o}

=20×12=10NC1m2= 20 \times \frac{1}{2} = 10NC^{- 1}m^{2}