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Question: A uniform electric field \(E = 2 \times 10^{3}NC^{- 1}\) is acting along the positive x – axis. The ...

A uniform electric field E=2×103NC−1E = 2 \times 10^{3}NC^{- 1} is acting along the positive x – axis. The flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane is

A

20NC−1m220NC^{- 1}m^{2}

B

30NC−1m230NC^{- 1}m^{2}

C

10NC−1m210NC^{- 1}m^{2}

D

40NC−1m240NC^{- 1}m^{2}

Answer

20NC−1m220NC^{- 1}m^{2}

Explanation

Solution

: Here, E=2×103NC−1E = 2 \times 10^{3}NC^{- 1} is along + direction x – axis surface area,

s=(10cm)2=102×10−4m2=10−2m2s = (10cm)^{2} = 10^{2} \times 10^{- 4}m^{2} = 10^{- 2}m^{2}

when plane is parallel to yz plane, θ=0o\theta = 0^{o}

So φ\varphi =E s cos⁡θ=2×103×10−2cos⁡0o=20NC−1m2\cos\theta = 2 \times 10^{3} \times 10^{- 2}\cos 0^{o} = 20NC^{- 1}m^{2}