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Question

Physics Question on Centre of mass

A uniform disc of radius R put over another uniform disc of radius 2R of same thickness and density, the peripheries of the two discs touch each other. The position of their centre of mass is

A

at R3\frac{R}{3} from the center of bigger disc towards the center of the smaller disc

B

at R5\frac{R}{5} from the center of the bigger disc towards the center of the smaller disc

C

at 2R5\frac{2R}{5} from the center of the bigger disc towards the center of the smaller disc

D

at 2R5\frac{2R}{5} from the center of the smaller disc

Answer

at R5\frac{R}{5} from the center of the bigger disc towards the center of the smaller disc

Explanation

Solution

Distance of C.M. from centre of big disc x=r2aR2+r2x = \frac{r^2 a}{R^2 +r^2} r- radius of small disc R- radius of big disc a- distance between the centres of discs