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Question

Physics Question on Newtons Laws of Motion

A uniform disc of radius R and mass M is free to rotate only about its axis. A string is wrapped over its rim and a body of mass m is tied to the free end of the string as shown in the figure. The body is released from rest. Then the acceleration of the body is :

A

2mg2m+M\frac{2 mg}{ 2 m + M }

B

2Mg2m+M\frac{2 Mg}{ 2 m + M }

C

2mg2M+m\frac{2 mg}{ 2 M + m }

D

2Mg2M+m\frac{2 Mg}{ 2 M + m }

Answer

2Mg2m+M\frac{2 Mg}{ 2 m + M }

Explanation

Solution

mgT=mamg - T = ma RT=IRT = I\propto RT=MR22.aRRT = \frac{MR^{2}}{2}. \frac{a}{R} T=Ma2T = \frac{Ma}{2} mgMa2=mamg - \frac{Ma}{2} = ma mga(M2+m)mg - a\left(\frac{M}{2}+m\right) mga(M+2m2)mg - a\left(\frac{M+2m}{2}\right) a=2mgM+2ma = \frac{2mg}{M+2m}