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Question

Physics Question on rotational motion

A uniform disc of mass 0.5kg0.5\, kg and radius rr is projected with velocity 18m/s18 \,m / s at t=0t=0 s on a rough horizontal surface It starts off with a purely sliding motion at t=0st=0\, s After 2s2\, s it acquires a purely rolling motion (see figure) The total kinetic energy of the disc after 2s2 \,s will be ______ JJ (given, coefficient of friction is 0.30.3 and g=10m/s2)
A uniform disc of mass

Answer

The correct answer is 54.
a=−μk​g=−3
V=18−3×2
V=12m/s
KE=21​mv2+21​2mr2​r2v2​
KE=43​mv2
KE=3×18=54J