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Question

Physics Question on thermal properties of matter

A uniform cylindrical rod of length LL and radius rr, is made from a material whose Young's modulus of Elasticity equals YY. When this rod is heated by temperature TT and simultaneously subjected to a net longitudinal compressional force FF, its length remains unchanged. The coefficient of volume expansion, of the material of the rod, is (nearly) equals to :

A

F/(3πr2YT)F /\left(3 \pi r ^{2} YT \right)

B

3F/(πr2YT)3 F /\left(\pi r ^{2} YT \right)

C

6F/(πr2YT)6 F /\left(\pi r ^{2} YT \right)

D

9F/(πr2YT)9 F /\left(\pi r ^{2} YT \right)

Answer

3F/(πr2YT)3 F /\left(\pi r ^{2} YT \right)

Explanation

Solution

\therefore Length of cylinder remains unchanged
so (FA)Compressive=(FA)Thermal\bigg(\frac{F}{A}\bigg)_{Compressive} \, \, = \bigg(\frac{F}{A}\bigg)_{Thermal}
Fπr2YαT\frac{F}{\pi r^2} \, Y \alpha T
(α\alpha is linear coefficient of expansion)
αFYTπr2\therefore \, \, \alpha \frac{F}{YT \pi r^2}
\therefore The coefficient of volume expansion γ\gamma = 3α3\alpha
γ=3FYTπr2\therefore \, \, \gamma \, \, = \, \, 3 \frac{F}{YT \pi r^2}