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Question

Physics Question on System of Particles & Rotational Motion

A uniform circular disc of radius 50 cm at rest is free to turn about an axis which is perpendicular to its plane and passes through its centre. It is subjected to a torque which produces a constant angular acceleration of 2.0rads22.0 \, rad \, s^{-2}. Its net acceleration in ms2ms^{-2} at the end of 2.0 s is approximately :

A

7

B

6

C

3

D

8

Answer

8

Explanation

Solution

Particle at periphery will have both radial and tangential acceleration
at=Rα=0.5×2=1m/s2a_t = R_{\alpha} = 0.5 \times 2 = 1 \, m/s^2
ω=ω0+αt\omega = \omega_0 + \alpha t
ω=0+2×2=4\omega = 0 + 2 \times 2 = 4 rad/sec
ac=ω2R=(4)2×0.5=16×0.5=8m/s2a_c = \omega^2 R = (4)^2 \times 0.5 = 16 \times 0.5 = 8 \, m/s^2
atotal=ap2+ac2=12+828m/s2a_{total} = \sqrt{a^2_p + a_c^2} = \sqrt{1^2 + 8^2} \approx 8 m/ s^2