Solveeit Logo

Question

Physics Question on Lenz law

A uniform but time-varying magnetic field B(t) exists in a circular region of radius a and is directed into the plane of the paper as shown. The magnitude of the induced electric field at point P at a distance r from the centre of the circular region

A

is Zero

B

decreases as 1/r

C

increases ac r

D

decreases as 1/r21/r^2

Answer

decreases as 1/r

Explanation

Solution

EdI=dϕdt=SdBdt\int E \cdot dI = \bigg| \frac{d\phi}{dt} \bigg| = S \bigg|\frac{dB}{dt} \bigg| or E(2πr)=πa2dBdt\, \, \, \, \, \, \, E(2 \pi r) = \pi a^2 \bigg|\frac{dB}{dt} \bigg| Forra,For \, r \ge a, E=a22rdBdt\therefore \, \, \, \, \, \, \, \, \, \, \, \, E = \frac{a^2}{2r} \bigg|\frac{dB}{dt} \bigg| \therefore Induced electric field 1/r\propto 1 /r Forra,For \, r \le a, E(2πr)=πr2dBdt\, \, \, \, \, \, \, \, \, \, E(2\pi r) = \pi r^2 \bigg| \frac{dB}{dt} \bigg| or E=r2dBdt \, \, \, \, \, \, \, \, \, \, \, \, \, \, E = \frac{r}{2} \bigg| \frac{dB}{dt} \bigg| ot Er \, \, \, \, \, \, \, \, \, \, \, \, \, \, E \propto r Atr=a,E=a2dBdtAt \, \, \, \, \, \, \, \, \, \, r = a , E = \frac{a}{2} \bigg| \frac{dB}{dt} \bigg| Therefore, variation of E with r (distance from centre) will be as follows: