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Question: A uniform beam of weight W is support horizontally by means of supports A and B at its ends. Find th...

A uniform beam of weight W is support horizontally by means of supports A and B at its ends. Find the reaction at A immediately after B is withdrawn.

A

W/4

B

3W/4

C

W/2

D

W

Answer

W/4

Explanation

Solution

When the support ‘B’ is withdrawn, the beam starts turning about A. Angular acceleration of beam about A, when B is withdrawn

α = WL2I=WL2WL23g=3g2LL2\frac{\frac{WL}{2}}{I} = \frac{\frac{WL}{2}}{\frac{WL^{2}}{3g}} = \frac{3g}{2L}\frac{L}{2} = 3g4\frac{3g}{4}

Now, W − R = Wg\frac{W}{g}at

W − R = 3g4\frac{3g}{4}×Wg\frac{W}{g}

W − R = 3W4\frac{3W}{4} ⇒ R = W/4

Hence, (1) is correct.