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Question: A two-digit number from \[10\] to \[99\], inclusive, is chosen at random. What is the probability th...

A two-digit number from 1010 to 9999, inclusive, is chosen at random. What is the probability that this number is divisible by 55 ?
A) 15\dfrac{1}{5}
B) 29\dfrac{2}{9}
C) 1090\dfrac{{10}}{{90}}
D) 1819\dfrac{{18}}{{19}}
E) 1991\dfrac{{19}}{{91}}

Explanation

Solution

Here we will use the formula for finding the probability which states that the probability for occurring any event will be equals to Number of favorable outcomes divided by the total number of favorable/possible outcomes:
Probability=Number of outcomesTotal number of outcomes{\text{Probability}} = \dfrac{{{\text{Number of outcomes}}}}{{{\text{Total number of outcomes}}}}

Complete step-by-step solution:
Step 1: First of all, we will calculate the total number that exists 9999. If we start from 1010 and end with inclusive 9999 , the total number is 9090.
\RightarrowThe total number of outcomes is equal to 9090.
Step 2: Now, we will find out how many numbers are there between 1010 9999 which are completely divisible by 55 because we need to find the probability of that number which is divisible by 55.
As we know, a number is divisible by
55 only when it ends with either
00 or 55.
So, the numbers divisible by 55 from 1010 to 9999 are as below:
10\Rightarrow 10, 1515, 2020, 2525, 3030, 3535, 4040,4545, 5050,5555, 6060,6565, 7070,7575,8080,8585,9090,9595 .
There is a total 1818 number which is divisible by 55.
\RightarrowThe number of favorable outcomes is equal to 9090.
Step 3: Now, we will use the probability formula for calculating the answer. By substituting the values of the number of outcomes and the total number of outcomes, we get:
Probability=1890\Rightarrow {\text{Probability}} = \dfrac{{{\text{18}}}}{{{\text{90}}}}
By dividing into the RHS side of the expression Probability=1890{\text{Probability}} = \dfrac{{{\text{18}}}}{{{\text{90}}}} , we get:
Probability=15\Rightarrow {\text{Probability}} = \dfrac{{\text{1}}}{5}

\therefore Option A is correct.

Note: Students need to remember some basic points about the probability that the range of the probability will always lie between 0P(A)10 \leqslant {\text{P(A)}} \leqslant {\text{1}} .
Also, you should remember that the number of outcomes will always be less than the total number of outcomes.