Question

A TV transmitter has a range of $50\, km$. The height of the TV transmitter is (Radius of the earth, $R_{e}=6 \cdot 4 \times 10^{6}\, m$ )

• A. 195.3 m
• B. 186.5 m
• C. 206 m
• D. 175 m

Answer 1

Answer: (A)

195.3 m

Answer 2

Range, $d=\sqrt{2 R_{e} h_{T}}$ $50\, km =\sqrt{2 \times 6.4 \times 10^{6} \times h_{T}}$ $2500 \times 10^{6}=128 \times 10^{5} h_{T}$ $\frac{25000}{128}=h_{T}$ $h_{T}=195.3$