Question

A T.V. tower has a height of 100 m. How much population is covered by T.V. broadcast, if the average population density around the tower is $1000/Km^{2}$

• A. $39.5 \times 10^{5}$
• B. $19.5 \times 10^{6}$
• C. $29.5 \times 10^{7}$
• D. $9 \times 10^{4}$

Answer 1

Answer: (A)

$39.5 \times 10^{5}$

Answer 2

Radius of the area covered by T.V. telecast $d = \sqrt{2hR_{e}}$

Total population covered $= \pi d^{2} \times$population density $= 2\pi hR_{e} \times$ Population density

$= 2 \times 3.14 \times 100 \times 6.4 \times 10^{6} \times \frac{1000}{10^{6}} = 39.503 \times 10^{5}$