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Question: A turntable rotates at \(100 rev/min\). calculate the angular speed in rad/s and in degree/s....

A turntable rotates at 100rev/min100 rev/min. calculate the angular speed in rad/s and in degree/s.

Explanation

Solution

In this problem,we are going to apply the concept of rotational motion. We know that one revolution completes 2πradians2\pi \,{\text{radians}} and also 360 degrees and one minute has 60 seconds.

Complete step by step answer:
We know that the complete circle has 2πradians2\pi \,{\text{radians}}and one minute has 60 seconds.
Since one revolution completes 2πradians2\pi \,{\text{radians}}, 100 revolutions complete 2π×100radians2\pi \times 100\,{\text{radians}}.
Therefore, 100 rev/min converts into rad/s as follows,
100rev/min=100((1rev)(2πrad1rev))(1min)(60s1min)100\,{\text{rev}}/\min = \dfrac{{100\left( {\left( {1\,rev} \right)\left( {\dfrac{{2\pi \,rad}}{{1\,rev}}} \right)} \right)}}{{\left( {1\,\min } \right)\left( {\dfrac{{60\,s}}{{1\,\min }}} \right)}}
ω103πrad/s\omega \Rightarrow \dfrac{{10}}{3}\pi \,rad/s
Also, we know that one revolution is equal to 360 degrees.
Therefore, 100 rev/min converts into degree/s as follows,
100rev/min=100((1rev)(3601rev))(1min)(60s1min)100\,{\text{rev}}/\min = \dfrac{{100\left( {\left( {1\,rev} \right)\left( {\dfrac{{360^\circ }}{{1\,rev}}} \right)} \right)}}{{\left( {1\,\min } \right)\left( {\dfrac{{60\,s}}{{1\,\min }}} \right)}}
ω600degree/s\omega \Rightarrow 600\,{\text{degree}}/{\text{s}}
Therefore, 100 rev/min is equal to 600 degree/s.

Note: Once you convert rev/min into rad/s, you can directly convert rad/s into degree/s by multiplying the answer by 180π\dfrac{{180^\circ }}{\pi }. Here, the conversion of 100 rev/min into rad/s is 103π\dfrac{{10}}{3}\pi . Therefore, the direct conversion of this quantity into degree/s is 103πrad/s×180π=600degree/s\dfrac{{10}}{3}\pi \,rad/s \times \dfrac{{180^\circ }}{\pi } = 600\,{\text{degree/s}}.