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Question

Physics Question on Gravitation

A tunnel is dug along a diameter of the earth. The force on a particle of mass 'm' placed in the tunnel at a distance X from the center is

A

GMemR3x\frac{GM_em}{R^3}x

B

GMemR2x\frac{GM_em}{R^2}x

C

GMemR3x\frac{GM_em}{R^3x}

D

GMemR3x\frac{GM_emR^3}{x}

Answer

GMemR3x\frac{GM_em}{R^3}x

Explanation

Solution

F=GMmx2F = \frac{GM'm}{x^2} but Mx=MR\frac{M'}{x'} = \frac{M}{R'}