Solveeit Logo
Login

Question

Question: A tuning fork vibrating with a frequency of 500 Hz is kept close to the open end of a tube filled wi...

A tuning fork vibrating with a frequency of 500 Hz is kept close to the open end of a tube filled with water, as shown in figure. The water level in the tube is gradually lowered. When the water level is 17 cm below the open end, maximum intensity of sound is heard. If the room temperature is 20oC,20^{o}C, the speed of sound in air at this temperature is

A

330ms−1330ms^{- 1}

B

340ms−1340ms^{- 1}

C

350ms−1350ms^{- 1}

D

360ms−1360ms^{- 1}

Answer

340ms−1340ms^{- 1}

Explanation

Solution

Here, υ=500Hz\upsilon = 500Hz

L=17cm=17×10−2mL = 17cm = 17 \times 10^{- 2}m

As υ=v4L\upsilon = \frac{v}{4L}

∴v=υ(4L)=(500s−1)(4×17×10−2m)\therefore v = \upsilon(4L) = (500s^{- 1})(4 \times 17 \times 10^{- 2}m)

=340ms−1= 340ms^{- 1}