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Question

Physics Question on Waves

A tuning fork vibrates with frequency 256Hz256\, Hz and gives one beat per second with the third normal mode of vibration of an open pipe. What is the length of the pipe ? (Speed of sound in air is 340ms1340\, ms^{-1})

A

220 cm

B

190 cm

C

180 cm

D

200 cm

Answer

200 cm

Explanation

Solution

Given: Frequency of tuning fork =256Hz=256 Hz.
It gives one beat per second with the third normal mode of vibration of an open pipe.
Therefore, frequency of open pipe =(256+1)Hz=(256+1) Hz
Speed of sound in air is 340m/s340 m / s.
Now we know, frequency of third normal mode of vibration of an open pipe is given as
f=3vsound 2lf=\frac{3 v_{\text {sound }}}{2 l}
3×3402l=255\Rightarrow \frac{3 \times 340}{2 l}=255
l=3×3402×255=2m=200cm\Rightarrow l=\frac{3 \times 340}{2 \times 255}=2\, m =200\, cm