Question

A tuning fork of frequency 500 Hz is sounded on a resonance tube, the first and second resonance is obtained at 17 cm and 52 cm. The velocity of the sound in m/s is –

• A. 170
• B. 350
• C. 520
• D. 850

Answer 1

Answer: (B)

350

Answer 2

v = 2f (l₂ – l₁) = $\frac { 2 \times 500 } { 100 }$ (52 – 17) = 350 m/s