Solveeit Logo

Question

Question: A tuning fork of frequency 440 Hz resonates with a tube closed at one end of length 1.8 cm and diame...

A tuning fork of frequency 440 Hz resonates with a tube closed at one end of length 1.8 cm and diameter 5 cm in fundamental mode. The velocity of sound in air is

A

336 m s–1

B

343 m s–1

C

300 m s–1

D

350 m s–1

Answer

343 m s–1

Explanation

Solution

In the fundamental mode of vibrations.

(l+0.3D)=λ4=v4υ(l + 0.3D) = \frac{\lambda}{4} = \frac{v}{4\upsilon}

v=4υ(l+0.3D)\therefore v = 4\upsilon(l + 0.3D)

=4×440(0.18+0.3×0.05)= 4 \times 440(0.18 + 0.3 \times 0.05)

V = 343m s1s^{- 1}