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Question

Physics Question on Current electricity

A tuned amplifier circuit is used to generate a carrier frequency of 2MHz2\, MHz for the amplitude modulation. The value of LC\sqrt{LC} is

A

12π×106\frac{1}{2 \pi \times 10^{6}}

B

12×106\frac{1}{2 \times 10^{6}}

C

13π×106\frac{1}{3 \pi \times 10^{6}}

D

14π×106\frac{1}{4 \pi \times 10^{6}}

Answer

14π×106\frac{1}{4 \pi \times 10^{6}}

Explanation

Solution

By transistor as an oscillator
f=12πLCf=\frac{1}{2 \pi \sqrt{L C}}
where f=2MHz=2×106Hzf=2\, MHz =2 \times 10^{6}\, Hz and LC=?\sqrt{L C}=?
LC=12πf\Rightarrow \sqrt{L C}=\frac{1}{2 \pi f}
=12π×2×106=14π×106=\frac{1}{2 \pi \times 2 \times 10^{6}}=\frac{1}{4 \pi \times 10^{6}}