Question

A tube of length L is filled completely with an incompressible liquid of mass M and closed at both the ends. The tube is then rotated in a horizontal plane about one of its ends with a uniform angular velocity $\omega$. The force exerted by the liquid at the other end is :

• A. $\frac{(ML\omega^2)}{(2)}$
• B. $\frac{(ML^2\omega)}{(2)}$
• C. 2ML$\omega$2
• D. $\frac{(ML^2\omega^2)}{(2)}$

Answer 1

Answer: (A)

$\frac{(ML\omega^2)}{(2)}$

Answer 2

The centripetal force resulting from rotation is the force generated by the liquid at the other end.
The situation can be thought of as the liquid's centre of mass rotating at a distance of$\frac{L}{2}$ from the axis of rotation.
As a result, the liquid exerts force at the end.
=$M\omega^2\big(\frac{L}{2}\big)$ = ​$\frac{(ML\omega^2)}{(2)}$

Therefore, the correct option is (A): $\frac{(ML\omega^2)}{(2)}$