Question
Question: A tube filled with water and closed at both ends uniformly rotates in a horizontal plane about the O...
A tube filled with water and closed at both ends uniformly rotates in a horizontal plane about the OO' axis. The manometers A and B fixed in the tube at distances r1 and r2 from rotational axis indicate pressure p1 and p2 , respectively. Determine the angular velocity ω of rotation of the tube:
(A) ω=ρ(r12−r22)2(p2−p1)
(B) ω=ρ(r12+r22)2(p2−p1)
(C) ω=(p2−p1)2(r22−r12)
(D) ω=ρr1r22(p2−p1)
Solution
Hint We know Bernoulli equation relates the speed of the fluid at a point, the pressure at that point and the height of that point above the reference level. Bernoulli equation is given by:
P+ρgh+21ρv2= constant
Since height is the same for both A and B hence ρgh term can be neglected.
Complete Step by step solution
On applying Bernoulli equation separately for A and B we get,
For A, p1 is the reading shown in the barometer.
Hence, p1+ρgh+21ρv12= constant…… (1)
For B, p2 is the reading shown in the barometer.
Hence, p2+ρgh+21ρv22= constant…… (2)
From equation (1) and (2) we get
Now we know that v=rω
Therefore, above equation becomes
ω=ρ(r12−r22)2(p2−p1)
Hence the required angular velocity is, ω=ρ(r12−r22)2(p2−p1)
Option (A) is correct.
Note Bernoulli equation is just the application of work-energy theorem in the case of fluid flow. In the Bernoulli equation we make a few assumptions like the fluid is ideal i.e. incompressible and nonviscous, it has constant density, both points lie on a streamline, flow is steady and there is no friction.