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Question

Physics Question on Waves

A tube closed at one end containing air produces fundamental note of frequency 512Hz512\, Hz. If the tube is open at both the ends, the fundamental frequency will be

A

1024 Hz

B

256 Hz

C

1280 Hz

D

768 Hz.

Answer

1024 Hz

Explanation

Solution

Given: Frequency of fundamental note when tube is closed (n1)=512Hz\left(n_{1}\right)=512 \,Hz.
We know that frequency of fundamental note for closed organ pipe (n2)=v2l\left(n_{2}\right)=\frac{v}{2 l} and for open pipe (n1)=v4l\left(n_{1}\right)=\frac{v}{4 l} or n2=2n1=2×512n_{2}=2 n_{1}=2 \times 512
=1024Hz=1024 \,Hz