Solveeit Logo

Question

Question: A truck of mass \[500kg\] moving at \[4m/s\] collides with another truck of mass \[1500kg\] moving i...

A truck of mass 500kg500kg moving at 4m/s4m/s collides with another truck of mass 1500kg1500kg moving in the same direction at 2m/s2m/s. What is their common velocity just after the collision if they move off together?

Explanation

Solution

The impact can be either elastic or inelastic. Elastic collision follows both conservations of momentum and kinetic energy whereas inelastic collision doesn’t obey conservation of kinetic energy. The collision of trucks comes under Inelastic collision wherever kinetic energy is not conserved. Inelastic collision follows Conservation of Momentum. So we can conclude that momentum before the collision is equal to momentum after the collision.

Complete step by step solution:
The term Momentum indicates the quantity that a moving object holds. It is referred to as the product of mass and velocity and its units are kgms1kgm{s^{ - 1}}orNsNs. It is denoted by the letter PP. In this given question, collision of the truck is an inelastic collision that follows conservation of momentum.
Momentum P=m×vP = m \times v,
where mm is the mass of the truck and vvis the velocity of the truck.
By conservation of momentum,
Momentum before impact = Momentum after impact
Mass of the first truck, m1=500kg{m_1} = 500kg
Speed of the first truck, u1=4m/s{u_{1}} = 4m/s
Mass of the second truck, m2=1500kg{m_2} = 1500kg
Speed of the second truck, u2=2m/s{u_2} = 2m/s
Combined masses of both the trucks, m=1500+500=2000kgm = 1500 + 500 = 2000kg
Combined velocity is taken as vv
According to the law of conservation of momentum, we can say that
m1u1+m2u2=mv{m_1}{u_{1}} + {m_2}{u_{2}} = mv
500×4+1500×2=2000×v\Rightarrow 500 \times 4 + 1500 \times 2 = 2000 \times v
v=2000+30002000=2.5m/sv = \dfrac{{2000 + 3000}}{{2000}} = 2.5m/s

Note:
Once two bodies of equal masses undergo one-dimensional elastic collision, their velocities will get interchanged. Similarly, when an elastic body hits against another body of the same mass, primarily at rest, after the impact the first body comes to rest whereas the second body passes with the initial velocity of the first. When a light body strikes against a heavy body at rest, the light body bounces back after the collision with equal and opposite velocity while the heavy body remains at rest.