Question

A truck of mass 30,000kg moves up an inclined plane of slope 1 in 100 at a speed of 30 kmph. The power of the truck is (given $g = 10ms^{- 1})$

• A. 25 kW
• B. 10 kW
• C. 5 kW
• D. 2.5 kW

Answer 1

Answer: (A)

25 kW

Answer 2

As truck is moving on an incline plane therefore only component of weight $( m g \sin \theta )$ will oppose the upward motion

Power = force × velocity = $m g \sin \theta \times v$

$= 30000 \times 10 \times \left( \frac { 1 } { 100 } \right) \times \frac { 30 \times 5 } { 18 } = 25 \mathrm {~kW}$