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Question: A truck is to be driven 300 km on a highway at a constant speed of x kmph. Speed rules of the highwa...

A truck is to be driven 300 km on a highway at a constant speed of x kmph. Speed rules of the highway required that

30 £ x £ 60. The fuel costs Rs. 10 per litre and is consumed at the rate of 2 + x2600\frac { x ^ { 2 } } { 600 } litres per hour. The wages of the driver are Rs. 200 per hour. The most economical speed to drive the truck, in kmph is

A

30

B

60

C

30 3.3\sqrt { 3.3 }

D

) 20 3.3\sqrt { 3.3 }

Answer

60

Explanation

Solution

Time taken by the truck = hours

\ petrol consumed = (2+x2600)300x\left( 2 + \frac { x ^ { 2 } } { 600 } \right) \frac { 300 } { x } litre

\ expenses on traveling

E = 200 × 300x+(2+x2600)3000x\frac { 300 } { x } + \left( 2 + \frac { x ^ { 2 } } { 600 } \right) \frac { 3000 } { x }

= 60000x+6000x\frac { 60000 } { x } + \frac { 6000 } { x } + 5x

= 66000x\frac { 66000 } { x } + 5x

\ dEdx\frac { \mathrm { dE } } { \mathrm { dx } } = – 66000x2\frac { 66000 } { x ^ { 2 } } + 5 < 0 for all x Ī [30, 60]

\ most economical speed is 60 kmph