Question
Physics Question on work, energy and power
A truck accelerates from speed υto2υ. Work done in during this is
A
three times as the work done in accelerating it from rest to υ
B
same as the work done in accelerating it from rest to υ
C
four times as the work done in accelerating it from rest to υ
D
less than the work done in accelerating it from rest to υ
Answer
three times as the work done in accelerating it from rest to υ
Explanation
Solution
Work done to accelerate from 0 to v is, W1=21mv2
Work done to accelerate from v to 2v is
W2=21m(2v)2
⇒ΔW=W2−W1=21m(2v)2−21mv2
=4W1−W1=3W1