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Question

Physics Question on work, energy and power

A truck accelerates from speed υto2υ\upsilon \,to\, 2\upsilon. Work done in during this is

A

three times as the work done in accelerating it from rest to υ\upsilon

B

same as the work done in accelerating it from rest to υ\upsilon

C

four times as the work done in accelerating it from rest to υ\upsilon

D

less than the work done in accelerating it from rest to υ\upsilon

Answer

three times as the work done in accelerating it from rest to υ\upsilon

Explanation

Solution

Work done to accelerate from 00 to vv is, W1=12mv2W_{1}=\frac{1}{2} \,m v^{2}
Work done to accelerate from vv to 2v2 \,v is
W2=12m(2v)2W_{2} =\frac{1}{2} \,m\,(2 v)^{2}
ΔW=W2W1=12m(2v)212mv2\Rightarrow \Delta W =W_{2}-W_{1}=\frac{1}{2} \,m(2 v)^{2}-\frac{1}{2} \,m v^{2}
=4W1W1=3W1=4\, W_{1}-W_{1}=3 \,W_{1}