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Question: A triangular plate ABC is free to rotate about two points A and B on smooth horizontal floor. A forc...

A triangular plate ABC is free to rotate about two points A and B on smooth horizontal floor. A force F is applied perpendicular to AB so as to rotate the plate about A and B separately. If α12 are the corresponding acceleration for the cases then α1α2\frac { \alpha _ { 1 } } { \alpha _ { 2 } } will be

A

1

B

< 1

C

> 1

D

Dependent on the force and the dimensions of the

Answer

> 1

Explanation

Solution

The torque applied in both cases are equal in magnitude, that is equal to rF

Therefore τ1=τ2=rF\tau _ { 1 } = \tau _ { 2 } = \mathrm { rF }

IAα1=IBα2\mathrm { I } _ { \mathrm { A } } \alpha _ { 1 } = \mathrm { I } _ { \mathrm { B } } \alpha _ { 2 }

Since