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Question: A travelling wave passes a point of observation. At this point, the time interval between successive...

A travelling wave passes a point of observation. At this point, the time interval between successive crests is 0.2 seconds and

A

The wavelength is 5 m

B

The frequency is 5 Hz

C

The velocity of propagation is 5 m/s

D

The wavelength is 0.2 m

Answer

The frequency is 5 Hz

Explanation

Solution

Phase difference between two successive crest is 2π. Also, phase difference (Δφ)(\Delta\varphi) = 2πT\frac{2\pi}{T} time interval (Δt)(\Delta t)

2π=2πT×0.21T=5sec1n=5Hz2\pi = \frac{2\pi}{T} \times 0.2 \Rightarrow \frac{1}{T} = 5\sec^{- 1} \Rightarrow n = 5Hz