Question

A transverse wave is represented by : $y = \frac{10}{\pi} \sin \left(\frac{2\pi}{T}t-\frac{2\pi}{\lambda}x\right)$ For what value of the wavelength the wave velocity is twice the maximum particle velocity ?

• A. 40 cm
• B. 20 cm
• C. 10 cm
• D. 60 cm

Answer 1

Answer: (A)

40 cm

Answer 2

$V=2\left(V_{p}\right)_{max}$
$\because V=f \lambda$
$f \lambda =2\omega A$
$\lambda =4\pi A$
$=4\pi\times\frac{10}{\pi}$
$=40\,cm$