Question

A transverse wave is represented by $y = 2sin(ωt – kx)$ $cm$. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity, will be

• A. $4π$
• B. $2π$
• C. $π$
• D. $2$

Answer 1

Answer: (A)

$4π$

Answer 2

**The value of wavelength : **

$⇒ k = \frac{1}{A}$ $\bigg[\frac{ω}{k} = Aω\bigg]$

$=$ $\frac{1}{2}\; cm$

$⇒ \frac{2π}{λ} = \frac{1}{ 2}$ $cm$ $[ \lambda = Wavelength]$

$⇒ λ = 4π$ $cm$

Hence, the correct option is (A): $4π$