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Question: A transverse wave is described by the equation y = y<sub>0</sub> sin 2π (ft – x/a). The maximum part...

A transverse wave is described by the equation y = y0 sin 2π (ft – x/a). The maximum particle velocity is equal to four times the wave velocity if a is equal to (a wavelength )

A

πy0 / 4

B

πy0/2

C

πy0

D

2πy0

Answer

πy0/2

Explanation

Solution

The maximum particle velocity of a SHM of amplitude y0 and frequency f is 2πfY0 . The wave velocity is fλ. For 2π fy0 to be equal to 4fλ, λ has to be πy0 / 2 (Here λ = a).