Question
Question: A transverse wave is described by the equation y = y<sub>0</sub> sin 2π (ft – x/a). The maximum part...
A transverse wave is described by the equation y = y0 sin 2π (ft – x/a). The maximum particle velocity is equal to four times the wave velocity if a is equal to (a wavelength )
A
πy0 / 4
B
πy0/2
C
πy0
D
2πy0
Answer
πy0/2
Explanation
Solution
The maximum particle velocity of a SHM of amplitude y0 and frequency f is 2πfY0 . The wave velocity is fλ. For 2π fy0 to be equal to 4fλ, λ has to be πy0 / 2 (Here λ = a).