Question

A transverse progressive wave on a stretched string has a velocity of 10 ms^–1 and a frequency of 100 Hz. The phase difference between two particles of the string which are 2.5 cm apart will be

• A. $\pi/8$
• B. $\pi/4$
• C. $3\pi/8$
• D. $\pi/2$

Answer 1

Answer: (D)

$\pi/2$

Answer 2

$\lambda = v/n = \frac{10}{100} = 0.1m = 10cm$

Phase difference = $\frac{2\pi}{\lambda}$× path difference$= \frac{2\pi}{10}$× 2.5 = $\frac{\pi}{2}$