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Question: A transverse harmonic wave on a string is described by y(x, t) = 3 sin\(\left( 36t + 0.018x + \frac{...

A transverse harmonic wave on a string is described by y(x, t) = 3 sin(36t+0.018x+π4)\left( 36t + 0.018x + \frac{\pi}{4} \right) where x and y are in cm and t is in s. Which of the following statements is incorrect?

A

The wave is travelling in negative x-direction

B

The amplitude of the wave is 3 cm.

C

The speed of the wave is 20 m s–1

D

The frequency of the wave is 9π\frac{9}{\pi} Hz.

Answer

The frequency of the wave is 9π\frac{9}{\pi} Hz.

Explanation

Solution

The given transverse harmonic wave equations is

y=3sin(36t+0.018x+π4)y = 3\sin\left( 36t + 0.018x + \frac{\pi}{4} \right) ….. (i)

As there is positive sign between t and x terms therefore the given wave is travelling in the negative x directions. The standard transverse harmonic wave equations is

y=asin(ωt+kx+φ)y = a\sin(\omega t + kx + \varphi) ….. (ii)

Comparing (i) and (ii) we get

a=3cm,ω=36rads1,k=0.018radcm1a = 3cm,\omega = 36rads^{- 1},k = 0.018radcm^{- 1}

\thereforeAmplitude of wave, a = 3 cm

Frequency of the wave,

υ=ω2π=362π=18πHz\upsilon = \frac{\omega}{2\pi} = \frac{36}{2\pi} = \frac{18}{\pi}Hz

Velocity of the wave

v=ωk=36rads10.018radcm1=2000cms1=20ms1v = \frac{\omega}{k} = \frac{36rads^{- 1}}{0.018radcm^{- 1}} = 2000cms^{- 1} = 20ms^{- 1}