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Question

Physics Question on Ray optics and optical instruments

A transparent thin film of uniform thickness and refractive index n1=1.4n _{1}=1.4 is coated on the convex spherical surface of radius RR at one end of a long solid glass cylinder of refractive index n2=1.5n_{2}=1.5, as shown in the figure. Rays of light parallel to the axis of the cylinder traversing through the film from air to glass get focused at distance f1f _{1} from the film, while rays of light traversing from glass to air get focused at distance f2f _{2} from the film. Then

A

f1=3R| f_1 |=3R

B

f1=2.8R| f_1 |=2.8R

C

f2=2R| f_2 |=2R

D

f2=1.4R| f_2 |=1.4R

Answer

f2=2R| f_2 |=2R

Explanation

Solution

For air to glass
1.5f1=1.41R+1.51.4R\frac{1.5}{f_{1}}=\frac{1.4-1}{R}+\frac{1.5-1.4}{R}
f1=3R\therefore f_{1}=3 \,R
For glass to air.
1f2=1.41.5R+11.4R\frac{1}{f_{2}}=\frac{1.4-1.5}{-R}+\frac{1-1.4}{-R}
f2=2R\therefore f_{2}=2\, R