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Question: A transparent sphere of radius R and refractive index $\mu$ is kept in air. At what distance from th...

A transparent sphere of radius R and refractive index μ\mu is kept in air. At what distance from the surface of the sphere should a point object be placed so as to form a real image at the same distance from the surface of sphere?

A

R/μ\mu

B

μ\muR

C

Rμ1\frac{R}{\mu-1}

D

Rμ+1\frac{R}{\mu+1}

Answer

Rμ1\frac{R}{\mu-1}

Explanation

Solution

For an object placed at the first principal focal point of a sphere, rays become parallel after the first refraction. These parallel rays then refract at the second surface, converging at the second principal focal point. For a sphere, the principal focal length from the surface is f=Rμ1f = \frac{R}{\mu-1}. If the object is placed at this distance from the first surface, the image will be formed at the same distance from the second surface, and it will be real (since μ>1\mu > 1).