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Question: A transparent cube of \(15cm\) edge contains a small air bubble. Its apparent depth when viewed thro...

A transparent cube of 15cm15cm edge contains a small air bubble. Its apparent depth when viewed through one face is 6cm6cm and when viewed through the opposite face is 4cm4cm. Then the refractive index of the material of the cube is:
A. 2.02.0
B. 2.52.5
C. 1.61.6
D. 1.51.5

Explanation

Solution

In order to solve this question you have to know the relationship between the real depth, apparent depth, and the refractive index of the material. Also, you have to know the concept of refraction of light in order to understand the real and apparent depth.

Formula used:
The Refractive index of the material is given by,

μ=DrealDapparent\mu = \dfrac{{{D_{real}}}}{{{D_{apparent}}}}

Where μ\mu is the refractive index of the material

Dreal{D_{real}} is the real depth of the object
Dapparent{D_{apparent}} is the apparent depth of the object

Complete step by step solution:
Here, in the question, it is given that the actual depth is 15cm15cm
And also given that the apparent depth, when viewed through one face, is 6cm6cm
So, let us consider the bubble be at a distance xcmxcm when viewed through one face
Hence, according to the formula of the refractive index of the material, we have

μ=DrealDapparent\mu = \dfrac{{{D_{real}}}}{{{D_{apparent}}}}

On putting the required values, we have

μ=x6 \Rightarrow \mu = \dfrac{x}{6} ……….(i)

Now, when viewed through the opposite face we have the real depth as (15x)cm(15 - x)cm and the apparent depth is given in the question that is 4cm4cm.
On putting in the formula we have,

μ=15x4 \Rightarrow \mu = \dfrac{{15 - x}}{4} ……..(ii)

Now, from equation (i) and (ii), we get

x6=15x4 \Rightarrow \dfrac{x}{6} = \dfrac{{15 - x}}{4}

We have to solve the above equation for finding the value of xx

4x=906x \Rightarrow 4x = 90 - 6x

On further solving, we get

x=9 \Rightarrow x = 9

Now, substitute the value in the equation (i), we get

μ=96 \Rightarrow \mu = \dfrac{9}{6}

On further solving, we have

μ=1.5\mu = 1.5
Thus, the refractive index of the material of the cube is 1.51.5

Therefore, the correct option is (D).

Note: Remember that the real depth is the actual distance of an object which is under the surface and can be measured by submerging a perfect ruler while apparent depth is the distance of an object in a denser medium when seen from the rarer medium. Also, remember that the value of apparent depth is smaller than the real depth if the refractive index of the material is greater than the medium in which the observer is present. Also, the converse is also true.