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Question

Physics Question on Alternating current

A transmitter transmits at a wavelength of 300m300\, m. A condenser of capacitance 2.4μF2.4\, \mu F is being used. The value of the inductance for the resonant circuit is approximately

A

104H10^{-4}H

B

106H10^{-6}H

C

108H10^{-8}H

D

1010H10^{-10}H

Answer

108H10^{-8}H

Explanation

Solution

Given, l=330m,l =330\, m, c=3×108m/sc=3 \times 10^{8} m / s Frequency, n=cλ=3×108300=106Hzn=\frac{c}{\lambda}=\frac{3 \times 10^{8}}{300}=10^{6} Hz Resonance frequency n=12πLCn =\frac{1}{2 \pi \sqrt{L C}} or LC=12πn\sqrt{L C} =\frac{1}{2 \pi n} or LC=14π2n2L C=\frac{1}{4 \pi^{2} n^{2}} Here, C=2.4×106FC=2.4 \times 10^{-6} F L=14π2(106)2×2.4×106\therefore L =\frac{1}{4 \pi^{2}\left(10^{6}\right)^{2} \times 2.4 \times 10^{-6}} =108H=10^{-8} H