Question

A transistor having b equal to 80 has a change in base current of 250 mA, then the change in collector current is –

• A. (250 – 80)mA
• B. (250 + 80)mA
• C. $\frac{250}{80}$mA
• D. 80 × 250 mA

Answer 1

Answer: (D)

80 × 250 mA

Answer 2

Using b = $\frac{I_{c}}{I_{b}}$

We get Ž I_c = I_b × b = 250 × 80 mA