Question
Physics Question on Semiconductor electronics: materials, devices and simple circuits
A transistor has an α = 0.95. Then β is :
A
0.95
B
1.5
C
19
D
(19+)−1
Answer
19
Explanation
Solution
β=α/(l−α) = 0.95/0.05 = 19
A transistor has an α = 0.95. Then β is :
0.95
1.5
19
(19+)−1
19
β=α/(l−α) = 0.95/0.05 = 19