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Question: A transistor connected in common emitter mode,the voltage drop across the collector is 2V and \(\bet...

A transistor connected in common emitter mode,the voltage drop across the collector is 2V and β\beta is 50, the base current if RCR_{C} is 2kΩ2k\Omega is

A

40μA40\mu A

B

20μA20\mu A

C

30μA30\mu A

D

15μA15\mu A

Answer

20μA20\mu A

Explanation

Solution

: using , IC=VCERC=22×103=103=1mAI_{C} = \frac{V_{CE}}{R_{C}} = \frac{2}{2 \times 10^{3}} = 10^{- 3} = 1mA

β=ICIB\therefore\beta = \frac{I_{C}}{I_{B}}

IB=ICβ=10350A=20μAI_{B} = \frac{I_{C}}{\beta} = \frac{10^{- 3}}{50}A = 20\mu A