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Question

Physics Question on Alternating current

A transformer operating at primary voltage 8 kV and secondary voltage 160 V serves a load of 80 kW. Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be

A

800 Ω and 1.06 Ω

B

10 Ω and 500 Ω

C

800 Ω and 0.32 Ω

D

1.06 Ω and 500 Ω

Answer

800 Ω and 0.32 Ω

Explanation

Solution

(8×103)2RP=80×103\frac{(8 × 10^3)^2}{R_P} = 80 × 10^3

RP=800ΩR_P = 800 Ω

(160)2Rs=80×103\frac{(160)^2}{R_s} = 80×10^3

Rs=0.32ΩR_s = 0.32 Ω