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Question

Physics Question on Alternating current

A transformer is used to light a 100W100\, W and 110V110\, V lamp from a 220V220\, V mains. If the main current is 0.5A0.5\, A, the efficiency of the transformer is approximately

A

0.3

B

0.5

C

0.9

D

0.1

Answer

0.9

Explanation

Solution

The efficiency of transformer
= Energy obtained from the secondary coil  Energy given to the primary coil =\frac{\text { Energy obtained from the secondary coil }}{\text { Energy given to the primary coil }}
or η= Output power  Input power \eta=\frac{\text { Output power }}{\text { Input power }}
or η=VsIsVPIp\eta=\frac{V_{s} I_{s}}{V_{P} I_{p}}
Given, VsIs=100W,Vp=220V,Ip=0.5AV_{s} I_{s}=100\, W,\, V_{p}=220\, V,\, I_{p}=0.5\, A
Hence, η=100220×0.5=0.90=90%\eta=\frac{100}{220 \times 0.5}=0.90=90 \%