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Question

Physics Question on Alternating current

A transformer has an efficiency of 80%. It is connected to a power input of 5kW5 \,kW at 200V200\, V . If the secondary voltage is 250V250\, V , the primary and secondary currents are respectively

A

25 A, 20 A

B

20 A, 16 A

C

25 A, 16 A

D

40 A, 25 A

Answer

25 A, 16 A

Explanation

Solution

Efficiency=output powerinput powerEfficiency=\frac{output\text{ }power}{input\text{ }power}
Input power =5000 =5000\text{ } W,
Input voltage =200 V=200\text{ }V
\therefore Primary current, Ip=5000200=25A{{I}_{p}}=\frac{5000}{200}=25\,A
Output power =5000×80100=4000W=5000\times \frac{80}{100}=4000W
Output voltage =250 V=250\text{ }V
Secondary current, Is=4000250=16A{{I}_{s}}=\frac{4000}{250}=16\,A